Re: NAQT sectional info (2)

Normalizing to Full Round Robins

What this
means is that teams' winning percentage multiplier as
established by preliminary play cannot be altered by
subsequent bracketed play or playoffs insofar as teams
continue to win or lose as "expected."

To
illustrate, consider a classic round robin outcome among 12
teams, with no upsets. Team A goes 11-0, B is 10-1, C is
9-2, D is 8-3, etc. Say that this tournament then
moves to playoff brackets after division into the top
four, middle four, and bottom four. D loses three more
matches, as expected, to A, B, and C. Their record has now
dropped to 8-6, and their winning percentage has dropped
from .727 to .571. Meanwhile, Team E, which started at
7-4 (.636), was the best of the middle bracket, and
finishes 10-4 (.714) as expected. For our purposes of
using winning percentage as a major factor in ordering
teams, clearly it would be unfair to rank E ahead of D.
What we do then, is assume a second full round robin,
even though only three games of it are actually
played. In addition to its three additional losses to A,
B, and C, Team D is given additional paper victories
over each of the teams in the middle and lower
brackets, and thus its adjusted winning percentage remains
just as it was before bracketing, at .727. Likewise, E
is given paper losses to A, B, C, and D, and paper
wins over the bottom bracket teams, and it's adjusted
winning percentage also remains where it began, at .571.
Going into those final three matches, .727 has to be
the lowest winning percentage that Team D can emerge
with, since they are not "supposed" to win any of the
three. They can, however, go up. If D wins one of those
last three matches, their final record is 9-5, and
their actual winning percentage has dropped from .727
to .643, though what they've done is score an upset.
So our response is to "normalize for another full
round robin," reflecting that result. They went 1-2
against the top three, but for our purposes we assume
they were also capable of going 8-0 against the bottom
eight that they would have also played in another full
round robin. So for our multiplier purposes, we use the
winning percentage of their presumed second round robin
record of 17-5 (8-3 in the first one, and 9-2 in the
second, with 8 of those games not actually being played
-- and for our purposes, their adjusted winning
percentage becomes .773. The percentage has gone up from
their original .727 thanks to the upset win. Had they
followed form and lost all three, we'd still assume that
the unplayed games would follow form, and that they'd
be 8-0 against the rest, so they'd be 16-6; the same
percentage as they started with. If it was Team C that D
beat, which went 0-3 in the bracket, since they also
lost to A and B, they would also now be presumed to
have finished with a record of 17-5 and a .773 winning
percentage for our calculations purposes.

This all
requires an intelligent look at playoff structures and
matches played in each tournament, but the approach
extrapolates on the same principles to cover any situation.
The point is that we use must use winning percentage
in an intelligent manner that hurts no team because
they had to add extra playoff or finals matches versus
stronger teams that they were supposed to lose to, and
also helps no team that gets extra matches versus
weaker teams that they are supposed to beat.

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